How to evaluate multiple expressions in one line?

We can use the , or comma operator to evaluate multiple expressions in one line. It evaluates from left-to-right and returns the value of the last item on the right or the last operand.

let x = 5;
x = (x++ , x = addFive(x), x *= 2, x -= 5, x += 10);
function addFive(num) {
return num + 5;
}

If you log the value of x it would be 27. First, we increment the value of x it would be 6, then we invoke the function addFive(6) and pass the 6 as a parameter and assign the result to x the new value of x would be 11. After that, we multiply the current value of x to 2 and assign it to x the updated value of x would be 22. Then, we subtract the current value of x to 5 and assign the result to x the updated value would be 17. And lastly, we increment the value of x by 10 and assign the updated value to x now the value of x would be 27.


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Made by Michael Sakhniuk

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